C program to evaluate the equation y=xn when n is a non-negative integer

				
					#include<stdio.h>
#include<conio.h> 
void main()
{
int count, n; 
float x,y;
printf(“Enter the values of x and n:”); 
scanf(“%f%d”, &x,&n);
y=1.0;
count=1; 
while(count<=n)
{
y=y*x; 
count++;
}
printf(“x=%f; n=%d; x to power n=%f”, x, n,y);
}
				
			
Output:

Enter the values of x and n: 2.5  4 

X=2.500000; n=4; x to power n= 39.062500

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