Objective: C program to solve knapsack problem using Greedy technique
Algorithm:
Step1: Start
Step2: Declare the variable.
Step3: Using the get function read the number of items, capacity of the bag, Weight of the item and value of the items.
Step4: Find out the small weight with high value using the find function.
Step5: Find out the optimal solution using the function findop ().
Step6: Display the optimal solution for the items.
Step7: Stop
# include<stdio.h>
void knapsack(int n, float weight[], float profit[], float capacity)
{
float x[20], tp = 0;
int i, j, u;
u = capacity;
for (i = 0; i < n; i++)
x[i] = 0.0;
for (i = 0; i < n; i++)
{
if (weight[i] > u)
break;
else
{
x[i] = 1.0;
tp = tp + profit[i];
u = u - weight[i];
}
}
if (i < n) x[i] = u / weight[i];
tp = tp + (x[i] * profit[i]);
printf("\nThe result vector is:- ");
for (i = 0; i < n; i++)
printf("%f\t", x[i]);
printf("\nMaximum profit is:- %f", tp);
}
int main()
{
float weight[20], profit[20], capacity;
int num, i, j;
float ratio[20], temp;
printf("\nEnter the no. of objects:- ");
scanf("%d", &num);
printf("\nEnter the wts and profits of each object:- ");
for (i = 0; i < num; i++)
{
scanf("%f %f", &weight[i], &profit[i]);
}
printf("\nEnter the capacityacity of knapsack:- ");
scanf("%f", &capacity);
for (i = 0; i < num; i++)
{
ratio[i] = profit[i] / weight[i];
}
for (i = 0; i < num; i++)
{
for (j = i + 1; j < num; j++)
{
if (ratio[i] < ratio[j])
{
temp = ratio[j];
ratio[j] = ratio[i];
ratio[i] = temp; temp =
weight[j]; weight[j] =
weight[i]; weight[i] = temp;
temp = profit[j];
profit[j] = profit[i];
profit[i] = temp;
}
}
}
knapsack(num, weight, profit, capacity);
getch();
return(0);
}
